#excerise

rs agarwal class 9 excerise 7a solution

2x - y = 3 \Rightarrow y = 2x - 3 \] Step 2: Substitute into the first equation: \[ 3x + 2(2x - 3) = 12 \] \[ 3x + 4x - 6 = 12 \] \[ 7x = 18 \] \[ x = \frac{18}{7} \] Step 3: Find \(y\): \[ y = 2 \times \frac{18}{7} - 3 = \frac{36}{7} - \fr